Anonymous

Module:Skills/Agility: Difference between revisions

From Melvor Idle
Put SC and GP costs separate from item costs
No edit summary
(Put SC and GP costs separate from item costs)
Line 73: Line 73:
function p.getObstacleCosts(obstacle)
function p.getObstacleCosts(obstacle)
local costs = {}
local costs = {}
local items = {}


if obstacle.gpCost > 0 then
if obstacle.gpCost > 0 then
Line 80: Line 81:
costs['SC'] = obstacle.scCost
costs['SC'] = obstacle.scCost
end
end
 
for j, itemCost in ipairs(obstacle.itemCosts) do
for j, itemCost in ipairs(obstacle.itemCosts) do
local item = Items.getItemByID(itemCost.id)
local item = Items.getItemByID(itemCost.id)
costs[item.name] = itemCost.quantity
items[item.name] = itemCost.quantity
end
end
costs['Items'] = items
return costs
return costs
end
end
Line 103: Line 105:
local costs = {}
local costs = {}
local obstacleCosts = p.getObstacleCosts(obstacle)
local obstacleCosts = p.getObstacleCosts(obstacle)
 
-- Make sure SC and GP appear at the top.
-- Make sure SC and GP appear at the top.
if obstacleCosts['GP'] then table.insert(costs, Icons.GP(obstacleCosts['GP'])) end
if obstacleCosts['GP'] then table.insert(costs, Icons.GP(obstacleCosts['GP'])) end
if obstacleCosts['SC'] then table.insert(costs, Icons.SC(obstacleCosts['SC'])) end
if obstacleCosts['SC'] then table.insert(costs, Icons.SC(obstacleCosts['SC'])) end
for item, amount in pairs(obstacleCosts) do
for item, amount in pairs(obstacleCosts['Items']) do
if item ~= 'GP' and item ~= 'SC' then
table.insert(costs, Icons.Icon({item, type='item', qty = amount, notext=true}))
table.insert(costs, Icons.Icon({item, type='item', qty = amount, notext=true}))
end
end
end


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